Cam Follower Mechanism, Energy Efficiency Rolling Mill Machinery

Cam Follower Mechanism Energy Efficiency

2009-09-08T23:05:00.000-07:00

You can see practical model of cam follower mechanism for clean energy. Follower move little bit and help cam to rotate 6 times more peripheral length. Cam can rotate 360 degree using two followers. Basic thing is follower move little bit and help to rotate cam 6 times more length at little less force(70% of force applied by follower). Please read the full post to know exactly the benefit of this system and how it works.

Model is about using cam for energy generation. You can see green arrow. That is force applied. Force is applied on cam using follower. Follower move up little bit and help to rotate cam at much more peripheral length.

You can see two video attached. You will get the idea.

When you apply force on follower, it will help cam to rotate. Follower move up little bit and help cam to rotate lot more peripheral length. We use the energy to move follower. And we get the energy by rotation of cam.

You can see green arrow in the video, that is force applied.

Question is what is the benefit of this system?

We get more energy on cam than we use to move follower.

We can decide how much follower move up for particular peripheral length of cam.

I mean follower move up only 1cm for helping cam to rotate 10cm peripheral length.

Force applied by follower will divide in two parts. One is tangential and second is towards the center of cam. Tangential part will help cam to rotate.

If we consider pressure angle 45`, you will get 70% of total force applied in tangential direction of cam.

So total energy loss by follower= force * distance

=100*0.01 (we consider force 100 N and distance 1cm (0.01 mtr))

=1N-mtr

Energy got by rotation of cam=Force *distance

=70*0.10 (we get 70% of total force in tangential direction so it is 70 and distance is 10 cm so it is 0.1meter)

=7N-mtr

If you use correctly, your production cost will be cut dramatically.

Model is about using cam for energy generation. force is applied on cam using follower. You can see green aerrow, that is force applied. Follower come down little bit and help to rotate cam at much more Peripheral length.

Click on figure for large view. It is about using Cam for increase energy efficiency. Cam are generally used to open and close valve of IC Engine. I am going to show you another use. Left side initial position. Right side final position. Redius of cam continuously decrease.Sliding weight (MG) applied on Cam. With the help of rope weight(MG*Cos(b)) is fixed with cam. We consider b as 45. So cos 45=.70. This fixed weight should be 0.70 MG. Which balance the sliding weight applied on cam in tengential direction. As sliding weight come down the fixed weight go up. But the twist is the redius of cam decrease nominal continuously. So sliding weight come down little bit and fixed weight go up much more. We consider sliding weight come dowm H2 height and fixed weight go up H1 height. We consider H1=5H2
Now we calculate energy loss by sliding weight=MG*Height
=MG*H2
Energy got by lifting fixed weight =MG*Cos(b)*Height
=MG*Cos45*H1
=.70MG*5H2 (Because H1=5H2)
=3.5MGH2
=3.5* Energy loss by sliding weight
So we get 3.5 times more energy than we loss. The ratio depend on the rate we decrease redius of cam and angle (b).

The Exact value of H1 is the length of curve from point A to point B. You can easily see black curve on cam from point A (Blue dot ) to point B(Blue dot).

The basic thing is weight (MG) comes down nominal height (H2) and help
to lift little less weight (0.70MG) at much higher height (H1=5H2)

I have explained that we can utilized the gravitational force to
rotate cam. I show that potential energy (mgh) we loss when sliding
weight come down is much less than potential energy we get by lifting
fixed weight. Fixed weight is lifted at equal height of peripheral
distance between starting and final position. It is H1. We reduce
radius of cam marginal so the sliding weight come down nominal . it
should be H2. Sliding weight (MG) applied in vertical downward
direction. When it applied on cam, it will be divided in two parts.
One is tangential ( MG cos (b)). and second is towards the center (MG
sin (b)). Tangential force will help to rotate cam and towards the
center force will generate friction.
The potential energy loss by sliding weight
= mgh
= MG* H2
The potential energy got by lifting fixed weight
=mgh
= MGcos(b)* H1
=MGcos(b)*5H2 (H1=5H2)
=cos(b)*5*MGH2 (b=45, cos(b)=0.70)
=0.70*5* MGH2
= 3.5 * energy loss by sliding plate.

H1=5H2 or may be H1=6H2 or H1=4H2
The ratio depend on the rate we decrease radius of cam. If the base
diameter is 50 mm , we consider two situation.
1. fall is 3mm through 180degree. (fall for cam design)
2. fall is 6 mm through 180 degree. (fall for cam design)
In first case H2=3mm
In second case H2=6 mm
In both case H1 is nearly same.

Click here to view model on you tube.

Friction force in this situation.

2009-07-12T06:19:00.000-07:00

Click here to view model on you tube.

Well friction in this situation depends on various factor.

1. Load towards the center of pulley. ( The main and most important factor.)

2. Smoothness and lubrication at contact surfaces.

3. Contact area (if contact area is more, friction will be more)

4. Materials of pulley and stationary plate.

If one material is soft and other is hard friction will be less. I prefer pulley or cam is hard and stationary plate which is in yellow colour should be soft. Or you can put some rubber type material at contact area.

5 Curvature or half circular contact. If you use half circular contact instead of line contact friction will be less.

Here I will discuss the main factor load.

Load towards the center will generate opposite direction friction force. Which oppose the rotation of pulley. You might asked me what is the exact value of this opposite load or friction force. I already told you it depends on many factor.

Ok I put 200 kg load on pulleys and try to analysis the situation. You can see 200 kg load divide on two pulleys and apply on each pulley 100 kg load.

This 100 kg further divided in two part one is tangential and second is towards the center. This tangential part will help to rotate pulley and towards the center part will generate opposite frictional force.

Tangential force will be cos30* 100=86 kg because here alpha is 30`

Towards the center force will be sin30 * 100=50 kg.

How to calculate opposite friction force from the value of towards the center force which is 50 kg?

I give you one example just to get overall idea.

What is you car weight may be 1000 kg

Now put your car gear in neutral and try to push it from your hand. You can push it. Your hand has not more than 200 kg power but still you can push 1000 kg weight car with your hand on flat surface remember not on mountain.

I give you another example.

You can see we can slide 100 kg load with the help of 10 kg load. Remember we are not going to lift 100 kg. We just push it. So we have to apply only little more force than friction force.

So the basic thing is if the load towards the center is 50 kg then the opposite friction force ( which oppose the rotation of pulley) will not be more than 5 kg. But still we include some other parameter like your contact area is not curvature, you use less lubrication and make more contact area than considering all this parameter frictional opposite force will not me more than 10 kg.

Mechanism To Increase Energy Efficiency

2009-06-02T00:20:00.000-07:00

The Exact value of H1 is the length of curve from point A to point B. You can easily see black curve on cam from point A (Blue dot ) to point B(Blue dot).

Stationary hydraulic force can help to rotate pulley.

2009-02-04T07:41:00.000-08:00

Stationary hydraulic or spring force can help to rotate pulley.Except pulley all other part in figure are stationary.

Energy Security, Global Warming and Engineering

2008-10-10T04:00:00.000-07:00

Research report is attached with this post (Energy security.pdf). You can download it from following link. It is about how we can use engineering to solve energy and global warming problem.
http://mechanicalresearch.info/report.pdf

Stationary Force Can Be Utilized To Do Work.

2008-07-17T22:07:00.000-07:00

Before explaining I want to clear some basic things.
v=Velocity. Rate of change in the position of an object
v=dx/dt Meters/Second.
a=Acceleration.
a=Rate of change of velocity.
a=dv/dt =dx/dt2.Meters/second2
Because v=dx/dt
Force (F) = M*a=M*dv/dt=M*dx/dt2 Kg-meters/second2 or Newton.
Work=Force* Distance traveled Newton-Meter.
But what happen when force is stationary or can not travel and object can travel at less than 90` Angel with direction of force.
Answer is "Stationary or static force will help to move object." You can use static gravity force. or static hydraulic or pheumatic force. Becuse of force is static, you will not lose any Energy to rotate pulley.

See Figure
There are two pulleys can rotate about their respective axis. Stationary force (MG) applied on pulleys by stationary plate (stationary plate is simply supported on pulleys.). This MG is equally divided and applied on each pulley in vertical downward direction(MG/2). This MG/2 will divided in two parts. one is tangential (MG/2 * Cos (Alpha)) and second is towards the center (MG/2 * Sin (Alpha)). Tangential force will help to rotate pulleys. Towards the center part will generate friction.
Uses and Advantages:

It will decrease manufacturing cost.
It will decrease electricity Bill.
It will help to reduce green house effect.
It provides clean energy.
It is cheap and available at every place.
It can use for both linear as well as for circular motion also.
It will improve quality of people’s life by giving clean and cheap energy.
It will help to reduce carbon dioxide in environment.

Force analysis ON Off Set Cam.

2008-06-15T22:19:00.000-07:00

You know Cam. It is generally used to open and close valve of IC Engine. In offset can the pointer is not towards the center. Now I do only one thing I dont change diameter of off set cam. You can understand by viewing my figure. So force by pointer (Stationary plate ) applied on cam ( without change of diameter, this is special cam.) You rotate that cam in any direction. The force applied by pointer (stationary plate) is same and constant. Now if you rotate cam (without change in diameter) in opposite direction, Stationary force applied by stationary pointer against to its motion, so you have to applied more force to rotate because you have to overcome the force applied by stationary pointer. But If you rotate cam in nearly same direction than it will help to rotate. who help (Stationary force applied by stationary plate or stationary pointer). Whom help ( Cam without change in diameter means pulley.)
To get idea read all post in this blog.
Uses and Advantages:

It will decrease manufacturing cost.
It will decrease electricity Bill.
It will help to reduce green house effect.
It provides clean energy.
It is cheap and available at every place.
It can use for both linear as well as for circular motion also.
It will improve quality of people’s life by giving clean and cheap energy.
It will help to reduce carbon dioxide in environment.

Mechanism that increase energy efficiency.

2008-03-02T23:25:00.000-08:00

As shown in figure two pulleys can rotate about their axis. Stationary plate is simply supported on these two pulleys. Now the weight of stationary plate applied on each pulley in vertical downward direction is Mg/2. This Mg/2 will divided in two parts. One is tangential and second is towards the center. Tangential part will help to rotate pulleys and toward the center part will generate the friction.

Mechanism that increase energy efficiency.

2007-12-27T04:27:00.000-08:00

To view figure click on Photos.

As shown in figure sliding plates can slide over fixed plates. Stationary plate is simply supported horizontally on sliding plates. Lubrication is provided at contact surfaces of stationary plate and sliding plates. Weight or load or force (mg) is applied at center of stationary plate. This load is equally divided and applied on each sliding plate in vertical downward direction (mg/2). This mg/2 cos(alpha) helps sliding plate to slide in nearly downward direction.

Force is stationary and it can help to slide the sliding plates at some angle.

Uses and Advantages:

It will decrease manufacturing cost.
It will decrease electricity Bill.
It will help to reduce green house effect.
It provides clean energy.
It is cheap and available at every place.
It can use for both linear as well as for circular motion also.
It will improve quality of people’s life by giving clean and cheap energy.
It will help to reduce carbon dioxide in environment.

Jigar Y. Patel